Open Channel Flow (Manning-Strickler)
Flow velocity · Discharge Q · Bed slope · Hydraulic radius · Froude number
Open Channel Calculator
Formulas & Fundamentals
v = kst · R2/3 · I1/2 [m/s]
kst = Strickler coefficient [m1/3/s]
R = hydraulic radius [m] | I = bed slope [–]
Q = v · A [m³/s]
R = A / P [m]
A = cross-sectional area | P = wetted perimeter
Fr = v / √(g · Dh)
Dh = A/T (hydraulic depth) | T = top water width
Fr < 1: subcritical flow (tranquil)
Fr > 1: supercritical flow (rapid)
Cross-section formulas
A = b·y | P = b + 2y | T = b
Trapezoid (side slope m = horiz./vert.):
A = (b + m·y)·y
P = b + 2y·√(1 + m²) | T = b + 2m·y
Circle (partial flow, θ in rad):
θ = 2·arccos(1 – 2h/D)
A = D²/8·(θ – sin θ)
P = D·θ/2 | T = D·sin(θ/2)
Strickler coefficient kst (typical values)
| Material / Condition | kst |
|---|---|
| Plastic, glass | 90–100 |
| Concrete smooth / precast | 80–90 |
| Concrete normal | 70–80 |
| Masonry rendered | 55–65 |
| Earth channel, well maintained | 40–50 |
| Natural channel, clean | 28–40 |
| Natural channel, vegetated | 15–28 |
Open Channel Flow – Fundamentals of Free-Surface Hydraulics
What does the Manning-Strickler formula describe?
The Manning-Strickler formula is the most widely used empirical equation for uniform, steady flow in open channels (canals, ditches, rivers, partially filled pipes). It relates the mean flow velocity v to the bed slope I, the hydraulic radius R, and the roughness coefficient kst:
Discharge follows as Q = v · A. The bed slope I = Δh/L describes the elevation difference per unit length of channel.
Flow regimes – Froude number Fr
| Fr | Flow regime |
|---|---|
| Fr < 1 | subcritical (tranquil, backwater possible) |
| Fr = 1 | critical flow |
| Fr > 1 | supercritical (rapid, shooting) |
Strickler vs. Manning
European standard: Strickler coefficient kst [m1/3/s]
Anglo-Saxon: Manning roughness n [s/m1/3]
Conversion: kst = 1/n
Example: n = 0.013 → kst ≈ 77
Cross-section shapes and their hydraulic properties
Rectangular channel
Simple calculation: A = b·y, P = b + 2y.
Hydraulically optimal at b/y = 2 (half-square): R = y/2 is then maximum.
Trapezoidal channel
Earth canals: m ≥ 1.0–1.5 (stability).
Hydraulically optimal: m = 1/√3 ≈ 0.577 (equilateral trapezoid).
Half-circle is the ideal hydraulic section.
Circular pipe (partial)
Max. v at h/D ≈ 81 %.
Max. Q at h/D ≈ 94 %.
(More favourable R/A ratio than full-bore flow.)
Worked example: trapezoidal earth channel
Problem:
Earth canal: bottom width b = 1.5 m, water depth y = 1.0 m, side slope m = 1.5, kst = 35 m1/3/s, bed slope I = 0.0005.
Solution:
- A = (1.5 + 1.5·1.0)·1.0 = 3.00 m²
- P = 1.5 + 2·1.0·√(1 + 1.5²) = 1.5 + 3.606 = 5.106 m
- R = 3.00 / 5.106 = 0.5876 m
- v = 35 · 0.58762/3 · √0.0005 = 35 · 0.6805 · 0.02236 = 0.532 m/s
- Q = 0.532 · 3.00 = 1.60 m³/s
- T = 1.5 + 2·1.5·1.0 = 4.5 m → Dh = 3.00/4.5 = 0.667 m
- Fr = 0.532 / √(9.81·0.667) = 0.532 / 2.559 = 0.208 → subcritical flow
Frequently Asked Questions
Summary
Strickler formula
v = kst·R2/3·I1/2
Q = v · A
Hydraulic radius
R = A / P
Measure of hydraulic efficiency
Froude number
Fr = v / √(g·Dh)
Fr < 1: subcritical
Typical applications
- Urban drainage: sizing of stormwater and wastewater sewers
- Hydraulic engineering: design of ditches, culverts, flood channels
- Flood protection: discharge capacity of watercourses and retention areas
- Agriculture: field drainage ditches, irrigation canals, land improvement
- Dam engineering: stilling basins, spillway chutes, overflow weirs
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