Eddy-Current Brake Calculator
Braking Force · Torque · Magnetic Flux Density · Braking Power · Deceleration
Eddy-Current Brake Calculator
Formulas & Symbols
Core Formulas
F = k × B² × v
F [N], k [N·s/(T²·m)], B [T], v [m/s]
M = F × r = k × B² × v × r
M [N·m], r = effective radius [m]
B = √(F / (k × v))
Required field for a desired braking force
P = F × v = k × B² × v²
P [W] – entirely converted to heat
a = F / m
a [m/s²], m = mass [kg]
Symbol Reference
| F | Braking force [N] |
| M | Braking torque [N·m] |
| k | Brake constant [N·s/(T²·m)] |
| B | Magnetic flux density [T] |
| v | Relative velocity [m/s] |
| r | Effective radius [m] |
| P | Braking power / heat [W] |
| a | Deceleration [m/s²] |
| m | Mass [kg] |
| σ | Electrical conductivity [S/m] |
Eddy-Current Brake – Fundamentals
What is an Eddy-Current Brake?
An eddy-current brake (also called a magnetic brake or retarder) is a contactless deceleration device based on the principle of electromagnetic induction. A moving electrically conductive object (e.g., a rotating metal disc) is placed in a strong magnetic field, inducing eddy currents in the conductor. By Lenz's law, these currents generate an opposing magnetic field that creates a braking force on the moving object.
The key advantage: there is no mechanical contact and therefore zero wear. All kinetic energy is converted entirely into heat in the conductor, which must be dissipated by cooling.
Advantages
- Zero mechanical wear
- Contactless operation
- Continuously variable (via field strength)
- Very fast control response
- Low maintenance, long service life
- No brake dust – clean operation
Disadvantages
- No holding force at v = 0
- Heat must be dissipated (cooling required)
- Higher design complexity
- Braking force strongly speed-dependent
- Weaker effect at low velocities
Physical Principle – Lenz's Law
When a conductor moves through a magnetic field, the changing magnetic flux through it induces an EMF according to Faraday's law. This drives eddy currents, which by Lenz's law create an opposing field and a braking (drag) force.
U_ind = −dΦ/dt = −B × l × v
Φ = magnetic flux [Wb], l = conductor length [m], v = velocity [m/s]
F = I_w × B × l = k × B² × v
k encapsulates geometry, conductivity, and effective area
Detailed Formula Derivation
1. Braking Force F
Example: k = 8, B = 0.8 T, v = 10 m/s → F = 8 × 0.64 × 10 = 51.2 N
2. Braking Torque M
Example: F = 51.2 N, r = 0.15 m → M = 7.68 N·m
3. Required Magnetic Flux Density
Example: F = 50 N, k = 8, v = 10 m/s → B = √(50/80) ≈ 0.79 T
4. Braking Power P
Example: k = 8, B = 0.8 T, v = 10 m/s → P = 8 × 0.64 × 100 = 512 W
5. Deceleration a
Example: F = 51.2 N, m = 500 kg → a = 0.102 m/s²
Practical Example: Roller Coaster Brake
Task:
A roller coaster (mass 1800 kg) must be slowed from 72 km/h (20 m/s) to 36 km/h (10 m/s). Available: aluminium fin brake with k = 12, electromagnets B = 1.0 T.
Solution at v = 20 m/s:
- F = 12 × 1.0² × 20 = 240 N
- a = 240 / 1800 = 0.133 m/s²
- P = 240 × 20 = 4 800 W (heat in fins)
At v = 10 m/s (end of braking):
- F = 12 × 1.0² × 10 = 120 N
- a = 120 / 1800 = 0.067 m/s²
- → Force halves at half speed! For constant deceleration: regulate B.
Frequently Asked Questions
Summary
Braking Force
F = k × B² × v
No wear, no contact
Braking Power
P = k × B² × v²
Fully converted to heat
Control
F ~ B² (quadratic)
Fast, continuously variable
Typical Applications
- High-speed trains – Linear eddy-current rail brakes (ICE, TGV)
- Truck retarders – Wear-free endurance braking on downhill grades
- Roller coasters – Safe, low-maintenance speed control
- Engine test benches – Defined load application without wear
- Magnetic safety brakes – Elevators and hoisting equipment
|
|
|
|