Roller Drive Calculator
Friction Force · Normal Force · Power · Torque · Drive Force
Roller Drive Calculator
Formulas & Symbols
Core Formulas
F = μ × N
F [N], μ = friction coefficient, N = normal force [N]
P = τ × ω = M × (2π × n / 60)
P [W], M [N·m], n [rpm], ω [rad/s]
F_R = f_R × m × g × cos(α)
f_R = rolling resistance coefficient, α = inclination [°]
F_A = F_R + m × g × sin(α)
Sum of rolling resistance and gravitational component
F_u = M / r
M = torque [N·m], r = roller radius [m]
Symbol Reference
| F | Friction / drive force [N] |
| μ | Friction coefficient [0…1] |
| N | Normal force [N] |
| P | Power [W / kW] |
| M (τ) | Torque [N·m] |
| ω | Angular velocity [rad/s] |
| n | Rotational speed [rpm] |
| f_R | Rolling resistance coeff. [–] |
| α | Inclination angle [°] |
| r | Roller radius [m] |
| η | Efficiency [0…1] |
Roller Drive – Fundamentals
What is a Roller Drive?
A roller drive (or powered roller conveyor) is a conveyor system in which driven rollers transport goods by friction. The driving force between the roller surface and the item being conveyed is generated entirely by static friction — with no positive (form-fit) connection. This makes roller drives flexible, robust, and low-maintenance.
Unlike chain drives or toothed belts, a roller drive transmits force solely through contact between roller and goods. The drive is typically provided by an electric motor with a gearbox that matches torque and speed to the required conveying velocity.
Advantages
- Simple, robust construction
- Well suited for unit loads
- Zero-pressure accumulation possible
- Quiet and low-vibration
- Long service life when properly designed
- Flexible conveyor lengths
Disadvantages
- Slip possible under overload
- Not suitable for very light goods
- Friction limits transmissible force
- Roller coating wear
- Contact pressure design is critical
Coulomb's Law of Friction
Static friction (μ_s) > kinetic friction (μ_k). When F > μ_s × N, slip occurs.
Example: μ = 0.35, N = 1000 N → F_max = 0.35 × 1000 = 350 N transmissible
Detailed Formula Derivation
1. Friction Force F
Maximum drive force per roller without slip.
2. Power P
Example: M = 50 N·m, n = 960 rpm → ω = 100.5 rad/s → P = 5 025 W ≈ 5.0 kW
3. Rolling Resistance and Drive Force
F_A = F_R + m × g × sin(α)
Example: m = 500 kg, f_R = 0.02, α = 5°
F_R ≈ 97.7 N, F_hang ≈ 428 N, F_A ≈ 526 N
4. Torque M and Peripheral Force
Example: P = 5 kW, n = 960 rpm, r = 80 mm → M ≈ 49.7 N·m, F_u ≈ 621 N
Practical Example: Logistics Roller Conveyor
Task:
A roller conveyor transports boxes (80 kg each) at v = 0.5 m/s on a 3° incline. Roller radius r = 75 mm, rolling resistance f_R = 0.02, efficiency η = 0.90.
Solution:
- F_R = 0.02 × 80 × 9.81 × cos(3°) ≈ 15.7 N
- F_incline = 80 × 9.81 × sin(3°) ≈ 41.1 N
- F_A = 15.7 + 41.1 = 56.8 N
- P_useful = 56.8 × 0.5 = 28.4 W
- P_motor = 28.4 / 0.90 ≈ 31.6 W
- n = 960 rpm → M = 31.6 / 100.5 ≈ 0.31 N·m
Frequently Asked Questions
Polyurethane: μ ≈ 0.4–0.6 – more abrasion-resistant than rubber.
Bare steel: μ ≈ 0.15–0.25 – for heavy loads on flat beds.
Plastic: μ ≈ 0.3–0.5 – quiet, corrosion-resistant.
Summary
Friction Force
F = μ × N
Basis of force transmission
Power
P = M × ω
η ≈ 0.85–0.95
Drive Force
F_A = F_R + m·g·sin(α)
Rolling resistance + gravity
Typical Applications
- Logistics & warehousing – Parcels, boxes, pallets on roller conveyors
- Automotive industry – Body assembly lines, conveyor tracks
- Food industry – Cleanroom-compatible conveying systems
- Airports – Baggage handling systems
- Mining & bulk materials – Conveyor belt drive and return drums
|
|
|
|