This function calculates the pooled standard deviation of two data series
The Pooled Standard Deviation is a weighted average of standard deviations for two or more groups. The individual standard deviations are averaged, with more “weight” given to larger sample sizes.
Die gepoolte Standardabweichung wird als Standardabweichung für eine Teilmenge berechnet.
To perform the calculation, enter two series of numbers. Then click the 'Calculate' button.
Input format
The data can be entered as a series of numbers, separated by semicolons or spaces. You can enter the data as a list (one value per line). Or from a column from Excel spreadsheet by copy & paste
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\(\displaystyle SD_p= \sqrt{\frac{(n-1)SD_x^2+(m-1)SD_y^2}{n+m-2}} \)
Calculation of the standard deviation of a sample
\(\displaystyle s=\sqrt{ \frac{1}{n-1} \sum^n_{i=1} (x_i-\overline{x})^2} \)
\(s^2\) Standard deviation \(n\) Number of data points \(x_i\) Single data point \(\overline{x}\) Mean of the sample
data set \( \displaystyle x= 3, 5, 7, 8 \)
data set \( \displaystyle y= 10, 16, 22, 27 \)
mean \( \displaystyle x= \frac{3+ 5+ 7+ 8}{4} =5.75\)
mean \( \displaystyle y= \frac{10+ 16+ 22+ 27}{4} =18.75\)
\( \displaystyle SD_x=\sqrt{\frac{1}{4-1}\cdot((3-5.75)^2+(5-5.75)^2+(7-5.75)^2+(8-5.75)^2)}\)
\( \displaystyle SD_x=\sqrt{\frac{1}{3}\cdot(7.5625+0.5625+1.5625+5.0625)}\)
\( \displaystyle SD_x=\sqrt{\frac{1}{3}\cdot 14.75} =\sqrt{4.9167}=\color{blue}{2.217}\)
\( \displaystyle SD_y=\sqrt{\frac{1}{4-1}\cdot((10-18.75)^2+(16-18.75)^2+(22-18.75)^2+(27-18.75)^2)}\)
\( \displaystyle SD_y=\sqrt{\frac{1}{3}\cdot(76.5625+7.5625+10.5625+68.0625)}\)
\( \displaystyle SD_y=\sqrt{\frac{1}{3}\cdot 162.75} =\sqrt{54.25} =\color{blue}{7.3655}\)
\( \displaystyle SD_p= \sqrt{\frac{(4-1)\cdot 2.217^2 +(4-1)\cdot 7.37^2}{4+4-2}} \)
\( \displaystyle SD_p= \sqrt{\frac{3\cdot 4.9167 +3\cdot 54.25}{6}} \)
\( \displaystyle SD_p= \sqrt{\frac{14.75 +162.75}{6}} =\sqrt{29.583} =\color{blue}{5.44}\)
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